In electrostatics we studied that potential between 2 point charges is v=1/4πε_0.Q/R.But in electrodynamics (current electricity)we studied ohm's law (v=iR) Is there any relation between these two ? How can we get expression v=iR from v=1/4πε_0.Q/R.

Open in App

Solution

Hope the image will be clear for you now.

Suggest Corrections

Similar questions

V=IR then,R=V/I.if we change the value of I and V is there any affect on R

Q. Match the column X to column Y

Column X (Physical Quantity/Law)	Column Y (formula)
(i) Electric current	(a) $R = R_{1} + R_{2} + R_{3}$
(ii) Potential difference	(b) $ρ = R A / l$
(iii) Ohm's Law	(c) $\frac{1}{R} = \frac{1}{R_{1}} + \frac{1}{R_{2}}$
(iv) Resistivity	(d) V=W/Q
(v) Series combination of resistor's	(e) I=Q/t
(vi) Parallel combination of resistor's	(f) V=IR

Q. The relation between the current I flowing through a conducting material, the potential V between its ends and its resistance R is given by:

V = I R

. The relation between Power

P

,current I and resistance R can be given as

I = \sqrt{\frac{P}{R}}

, which of the following is the correct relation between P in terms of V and R?

What does infinite resistance mean in circuit.

Ideally we have zero resistance does that mean that if I apply an potential difference V, it will come to zero (because of ohm law)

V=IR

BUT R=0

V=0

The Ohm's law states that at constant temperature the current flowing through a conductor is directly proportional to the potential difference across its ends . This means that I proportional to V. Two equate this we need to add a constant. This we get V=R*I . But why can't we write the same equation by adding a constant on the other side as I=R*V . How do we know which side to add the constant and how?

Join BYJU'S Learning Program

In electrostatics we studied that potential between 2 point charges is v=1/4πε0.Q/R.But in electrodynamics (current electricity)we studied ohm's law (v=iR) Is there any relation between these two ? How can we get expression v=iR from v=1/4πε0.Q/R.

Hope the image will be clear for you now.

In electrostatics we studied that potential between 2 point charges is v=1/4πε_0.Q/R.But in electrodynamics (current electricity)we studied ohm's law (v=iR) Is there any relation between these two ? How can we get expression v=iR from v=1/4πε_0.Q/R.