In FCR, Toluene can be prepared by:

C_{6} H_{6} + {C H}_{3} C l

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C_{6} H_{5} C l + {C H}_{4}

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C_{6} H_{6} + {C H}_{2} {C l}_{2}

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C_{6} H_{6} + {C H}_{3} C O C l

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Solution

The correct option is A $C_{6} H_{6} + {C H}_{3} C l$

Friedel–Crafts alkylation involves the alkylation of an aromatic ring with an alkyl halide using a strong Lewis acid $A l {C l}_{3}$ as the catalyst.With anhydrous aluminium chloride as a catalyst, the alkyl group attaches at the former site of the chloride ion.

Toulene is prepared by keeping -R as $C H_{3}$ group.

So Toulene is prepared by $C_{6} H_{6} {+ C H}_{3} C l$

Suggest Corrections

Similar questions

C_{6} H_{6} \to C_{6} H_{5} {C H}_{3}

C_{6} H_{6} + A + A l {C l}_{3} ⟶ C_{6} H_{5} C O {N H}_{2}

C_{6} H_{6}

(C_{6} H_{5} {C H}_{3})

C_{6} H_{6} + {H N O}_{3} + H_{2} {S O}_{4} 50^{0} - 60^{0} - ---- \to A S n + H C l - ---- \to B {C H}_{3} C O C l - ----- \to C

C

C_{6} H_{6}, C_{6} D_{6}

C_{6} T_{6}

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