wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In Fig. 38, ABCD and PQRC are squares such that AD = 22 cm and PC = y cm. If the area of the shaded region is 403 cm2,
then the value of y is

(a) 3 (b) 6 (c) 9 (d) 10

Open in App
Solution

Here, AD = 22 cm.
Area of square ABCD = (22)2 cm2 = 484 cm2
Area of square PQRC = y2 cm2
Now, as per the question
Area of shaded region = Area of square ABCD − Area of square PQRC
403=484-y2y2=484-403=81y=9
Hence, the correct option is (c).

flag
Suggest Corrections
thumbs-up
13
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Area of Irregular Shapes
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon