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Question

In Fig. 7.139, ABC=90 and BDAC. If BD = 8 cm and AD = 4 cm, find CD.

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Solution

In triangleABC and triangleADB
angleABC =angle ADB (right angle)
angleBAD = angleBAC (common angle)

180 - (angleABC + angleBAC ) = 180 - (angle ADB +angleBAD ​)
angleDBA = angleBCA (proved)
Hence both the triangles are similar.

In triangleADB
BDblank squared + DAblank squared = ABblank squared
16+64 = ABblank squared
AB = 4square root of 5

As we know
fraction numerator A B over denominator A C end fraction equals fraction numerator B D over denominator B C end fraction equals fraction numerator A D over denominator A B end fraction (Corresponding sides of similar triangles)
fraction numerator 4 square root of 5 over denominator A C end fraction equals 4 over 8 A C space equals 8 square root of 5 A D space plus space D C space equals 8 square root of 5 4 space plus thin space D C space equals space 8 square root of 5 C D space equals space 8 square root of 5 space minus 4

Therefore, CD = 8square root of 5 - 4 cm


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