In fig., in ∆ABC, AB = AC. The value of x is:
120o
130o
100o
80o
Here, ∠B + ∠C = 180o - 80o = 100o.
But, ∠B = ∠C therefore ∠C = 50o.
So, x = 180o - 50o = 130o.
The values of x and y are(a) x=130, y=120(b) x=120, y=130(c) x=120, y=120(d) x=130, y=130
In the figuere, if AE || DC and AB=AC,the value of ∠ABD is
In the given figure, if AE∥DC and AB=AC, the value of ∠ABD is
(a) 70∘
(b) 110∘
(c) 120∘
(d) 130∘