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Question

In Fig. the bar is uniform and weighing 500 N. How large must W be in N if T1 and T2 are to be equal ?

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Solution

Taking torque about the attachment point for W, we get
T1(0.4L)+T2(0.3L)+500(0.2L)=0
T=1000 N, where T1=T2=T
Fy=02TW500=0
W=1500 N

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