In figure $A B$ and $C D$ are two chords equidistant from the centre $O$ . $O P$ is the $⊥$ draw from centre $O$ to $A B$ . If $C D = 6 c m$ , find $P B$

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Solution

Chords equidistant from center are equal in length
$∴ A B = C D$
$∴ A B = C D = 6 c m$
Now $O P$ is $⊥$ to $A B$
$∴ A P = P B = \frac{A B}{2}$
$P B = \frac{6}{2} = 3 c m$ .

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In figure AB and CD are two chords equidistant from the centre O. OP is the ⊥ draw from centre O to AB. If CD=6 cm, find PB

Chords equidistant from center are equal in length ∴AB=CD∴AB=CD=6 cmNow OP is ⊥ to AB∴AP=PB=AB2PB=62=3 cm.

In figure $A B$ and $C D$ are two chords equidistant from the centre $O$ . $O P$ is the $⊥$ draw from centre $O$ to $A B$ . If $C D = 6 c m$ , find $P B$

Chords equidistant from center are equal in length
$∴ A B = C D$
$∴ A B = C D = 6 c m$
Now $O P$ is $⊥$ to $A B$
$∴ A P = P B = \frac{A B}{2}$
$P B = \frac{6}{2} = 3 c m$ .