Question

In figure, area of parallelogram is $64m^2.$Its sides are 16 m and 8 m.Find the height $h_{1}and{h}_2.$

• A. $h_1=4m\text{and}{h}_2=5m$
• B. $h_1=8m\text{and}{h}_2=4m$
• C. $h_1=9m\text{and}{h}_2=8m$
• D. $h_1=8m\text{and}{h}_2=10m$

Answer 1

The correct option is B $h_1=8m\text{and}{h}_2=4m$

Area of parallelogram = $\text{base}\times \text{height}$

$\text{Given Area}=64m^2$, sides 16 m and 8 m

When base = 8 m
$\text{Area = base}\times \text{height}\left(h_1\right)$
$64m^2=8m\times h_1$

$h_1=\frac{64}{8}$

$h_1=8m$

When base = 16 m
$\text{Area = base}\times \text{height}\left(h_2\right)$
$64m^2=16m\times h_2$

$h_2=\frac{64}{16}$

$h_2=4m$

$\therefore h_1=8m\text{and}{h}_2=4m$