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Question 4
In figure, BAAC,DEDF such that BA =DE and BF =EC. Show that ΔABCΔDEF

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Solution

Given in figure,
BAAC,DEDF such that BA = DE and BF = EC
To show : ΔABCΔDEF
Proof :
Since BF =EF
On adding CF both side, we get
BF +CF = EC +CF
BC=EF...(i)
In ΔABC and ΔDEFA=D=90[BAAC and CEDF]
BC = EF [from Eq.(i)]
and AB = DE [given]
ΔABCΔDEF [by RHS congruence rule]

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