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Series Combination of Cells

In figure, ...

Question

In figure, $C_{1} = C_{5} = 8.4 μ F$ and $C_{2} = C_{3} = C_{4} = 4.2 μ F$ . The applied potential is $V_{a b} = 220 V$ . The equivalent capacitance of the network between points $a$ and $b$ is $C$ . Then, find the value of $2 C$ .

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Solution

$\frac{1}{C} = \frac{1}{3.4} + \frac{1}{8.4} + \frac{1}{6.3}$
$C = 2.52$
$2 C = 5.04$

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C_{1} = C_{2} = C_{3} = C_{4} = 8

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; C_{5} = 10 μ C

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The effective capacitance between P and Q of the figure below is :

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A

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