Question

In figure $h$,

given $AB||CD$ then find the following giving reason.
If $\angle 1=(120-x{)}^o$ and $\angle 4={54}^o$
Then find the measured of $\angle 1$ and $\angle 5$ where $\angle 5=5x^o$.

Answer 1

From the figure $\angle 1+\angle 4=180$

Given $\angle 1=120-x\angle 4=54$

$120-x+54=180$

$x=174-180=-6$

$\angle 1=120-(-6)=126°$

Given $AB\parallel CD$

$\therefore \angle 1=\angle 5$

$\angle 5=126°$