The correct option is D 108o
InfigureAB∥CD∠PRB=2x(Given)AslinesABandPQintersectatR∠PRB=∠GRS⟹∠GRS=2xAlso,AB∥CD∠GRS+∠HSR=(sumofinteriorangleissupplementary∠HSR=3x(Given)⟹2x+3x=180⟹5x=1805⟹x=36∠EGA=2x(Given)∠EGA+∠EGR=180⟹2x+∠EGR=180⟹∠EGR=180−2xAlso∠GHS=∠EGR(Corrospondinganglesareequal)⟹∠GHS=180−2xPuttingvalueofx=36∠GHS=180−2×36=180−72=108⟹∠GHS=108Now∠GHS=∠CHF(Verticallyoppositeangles)Hence∠CHF=108