In figure, the wires P1Q1 and P2Q2 are made to slide on the rails with same speed of 5cms−1. In this region, a magnetic field of 1T exists. The electric current in the 9Ω resistance is
A
zero if both wires slide toward left
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B
zero if both wires slide in opposite directions
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C
0.2mA if both wires move toward left
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D
0.2mA if both wires move in opposite directions
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Solution
The correct options are B zero if both wires slide in opposite directions C0.2mA if both wires move toward left EMF induced according to Faraday's Law: E=dϕdt ϕ=BLx , where x is the distance from the origin For a single slider: |E|=BvL=1(0.05)(0.04)=2mV The sign depends on the direction of velocity. If same direction, Eeq=E=Bvl=2mV i=VReq=(2/10)=0.2mA If velocities in opposite direction: Eeq=0 ⇒i=0