In first 1000 natural numbers, how many numbers exists such that when divided by 7 leaves a remainder of 6?

142

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141

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143

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146

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Solution

The correct option is C
143

The numbers required will be 6, 13, 20, 27, 34, 41, ....., 1000

6 + (n-1) 7 = 1000

n = 143

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