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B
8 V
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C
6 V
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D
10 V
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Solution
The correct option is A 12 V
i=10−2t At t = 2, the potential difference across the inductor is, VL=Ldidt=−2×2=−4V The potential drop across the battery is 10 V. i=6A, at t = 2. The potential drop across the resistor is iR=6×1=6V VAB=−4+10+6=12V