In given figure find $x$

110^{0}

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120^{0}

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130^{0}

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140^{0}

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Solution

The correct option is A $110^{0}$
We know that sum of exterior angles of a triangle $=$ $360^{\circ}$

So, from figure we have,

$125^{o} + 125^{o} + x = 360^{o}$

$\Rightarrow x = 360^{o} - 250^{o} = 110^{\circ}$ .

Therefore, option $A$ is correct.

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In given figure find x

The correct option is A 1100We know that sum of exterior angles of a triangle = 360∘So, from figure we have,125o+125o+x=360o⇒x=360o−250o=110∘.Therefore, option A is correct.

In given figure find $x$

The correct option is A $110^{0}$
We know that sum of exterior angles of a triangle $=$ $360^{\circ}$

So, from figure we have,

$125^{o} + 125^{o} + x = 360^{o}$

$\Rightarrow x = 360^{o} - 250^{o} = 110^{\circ}$ .

Therefore, option $A$ is correct.