1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In given regular hexagon, if AD = 10 cm, AB = 5 cm and FB = 8.66 cm, find area of hexagon.

A
32.49 cm2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
64.95 cm2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
97.43 cm2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
129.9 cm2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 64.95 cm2Given: In regular hexagon all sides are equal AB=BC=CD=DE=EF=FA = 5 cm FO = BO = 12×FB = 12×8.66 = 4.33 cm Area of hexagon = Area of trapezium ADEF + Area of trapezium ADCB Area of hexagon = 12×(AD+EF)×FO + 12×(AD+BC)×BO =12×(AD+EF)×FO + 12×(AD+EF)×FO ........(∵ EF=BC and FO=BO) = (AD+EF)×FO = (AD+EF)×FB2 = (10+5)×8.662 = (15)×8.662= 15×4.33 = 64.95 cm2

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Area of combination of different shapes
MATHEMATICS
Watch in App
Explore more
Join BYJU'S Learning Program