Question

In graphite and diamond, the percentage of p-characters of the hybrid orbitals in hybridisation are respectively _________.

• A. $50$ and $75$
• B. $67$ and $75$
• C. $33$ and $25$
• D. $33$ and $75$

Answer 1

Answer: (B)

$67$ and $75$

$\%$ p-characters $=\frac{\text{p-orbitals}}{\text{total orbitals}}$

$s{p}^2$ in graphite

$s{p}^3$ diamond

$\therefore$ for Graphite, $\%$ p-characters $=\frac{2}{3}\times 100$

$=67\%$

For diamond, $\%$ p-characters $=\frac{3}{4}\times 100$

$=75\%$