Question

In graphite and diamond, the percentage of p-characters of the hybrid orbtials in hybridisation are respectively_______

• A. 50 and 75
• B. 67 and 75
• C. 33 and 25
• D. 33 and 75

Answer 1

The correct option is B 67 and 75

Correct option is B)
$$\text{\%p-characters}=\frac{\text{p-orbitals}}{\text{Total orbitals}}$$

$s{p}^2$ in graphite

$s{p}^3$ diamond

$\therefore \text{For Graphite, p-characters}=\frac{2}{3}\times 100=67\%$

$\text{For diamond, p-characters}=\frac{3}{4}\times 100=75\%$
Hence, option (b) is correct.