The percentage of s- character of the hybrid orbitals in ethane, ethene and ethyne are respectively:

50, 75, 100

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10, 20, 40

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25, 33, 50

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25, 50, 75

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Solution

The correct option is B $25, 33, 50$
Ethane Ethene Ethyne

$C H_{3} - C H_{3}$ $C H_{2} = C H_{2}$ $H C = C H$
$S P^{3} S P^{3}$ $S P^{2} S P^{2}$ $S P S P$

$% S = 25 %$ $% S = 33.33 %$ $% S = 50 %$
$% P = 75 %$ $% P = 66.67 %$ $% P = 50 %$

Hence, option C is correct.

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