In $H_{2}^{-}$ ion, the bond order is

zero

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1 / 2

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Solution

The correct option is C $1 / 2$
In $H_{2}^{-}$ ion, the bond order is $\frac{1}{2}$ .
$B . O = \frac{N_{b} - N_{a}}{2} = \frac{(2 - 1)}{2} = 0.5$

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