Question

In $H_2^{-}$ ion, the bond order is

• A. zero
• B. $1/2$
• C. $-1/2$
• D. $1$

Answer 1

Answer: (B)

$1/2$

In $H_2^{-}$ ion, the bond order is $\frac{1}{2}$.

$B.O=\frac{N_b-N_a}{2}=\frac{(2-1)}{2}=0.5$