Question

In how many ways can 5 girls and 3 boys be seated in a row so that no two boys are together ?

ANS : 14400
PLEASE ELABORATE THE LOGICAL CONSTRUCTION TO REACH ANSWER

Answer 1

Here In the question, there are 5 girls. 5 girls can be seated in 5P5=5x4x3x2x1=5! ways. After arranging the girls in 5 ways, boy can sit in 6 places, as given below by $ sign:

$G$ G$G$ G $G$

Now, the question says that no two boys can sit togerher. So there are 6 places where these 3 boys can sit. So now the boys can sit in 6P3.

Therefore, the total number of seating arrangements possible

=5P5 x 6P3

= 5 x 4 x 3 x 2 x 1 x 6 x 5 x 4 ways

=14400 ways