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Question

In how many ways can a pack of 52 cards be
(a)  divided equally among four players in order
(b)  formed into 4 groups of 13 cards each
(c)  divided into 4 sets, three of them having 17 cards each and the fourth just 1 card.


Solution

(a) $$\dfrac{52!}{(13!)^{4}}$$
(b) $$\dfrac{52!}{(13!)^{4} 4!}$$
(c) $$\dfrac{52!}{(17!)^{3}. 1! 3!}$$

Maths

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