CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

You have to divide a pack of $$52$$ cards equally among $$4$$ players. In how many ways the cards can be divided in $$4$$ sets, $$3$$ of them having $$17$$ cards each & the $$4^{th}$$ with $$1$$ card


A
52!4!3!(17!)3
loader
B
52!(3!)3(17!)
loader
C
52!(3!)(17!)
loader
D
52!(17!)3
loader

Solution

The correct option is A $$\displaystyle \frac{52!4!}{3!(17!)^3}$$
First select $$17$$ cards out of $$52$$ cards in $$^{52}C_{17}$$. 
Then select $$17$$ from the remaining $$35$$ cards in $$^{35}C_{17}$$. 
Then select $$17$$ again from the remaining $$18$$ in $$^{18}C_{17}$$ ways. 

Total no. of ways 
$$ =$$  $$ ^{52}C_{17} \times ^{35}C_{17} \times ^{18}C_{17} \times 1 \times ^4C_3$$
$$=$$   $$\displaystyle \frac{52!4!}{3!(17!)^3}$$

Maths

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image