In III group precipitation NH 4 Cl is added before adding NH 4 OH toA- prevent interference of P O 43-B- increase conc- of Cl -ionsC- decrease conc- of OH -D- increase conc- of OH -ions

The correct option is C decrease conc. of OH^−NH_4OH ⇌ NH^+_4 + OH^ NH_4Cl →Common ionNH^+_4 + Cl^ Due to common ion effect, conc. of OH^− ion decreases. Thu ...

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Byju's Answer

Standard XII

Chemistry

Ionic Radii and Ionisation Enthalpy (Group 2)

In III group ...

Question

In III group precipitation $N H_{4} C l$ is added before adding $N H_{4} O H$ to

decrease conc. of

O H^{-}

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prevent interference of

P O_{4}^{3 -}

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increase conc. of

C l^{-}

ions

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increase conc. of

O H^{-}

ions

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Solution

The correct option is A decrease conc. of $O H^{-}$
$N H_{4} O H ⇌ N H_{4}^{+} + O H^{-}$
$N H_{4} C l \to N H_{4}^{+} + C l^{-} Common ion$
Due to common ion effect, conc. of $O H^{-}$ ion decreases. Thus, precipitation of higher group cations as hydroxides is prevented.

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Similar questions

Q. In III group precipitation,

N H_{4} C l

is added before adding

N H_{4} O H

to.

Q. In the system :

F e (O H)_{3 (s)} ⇌ F e_{(a q)}^{3 +} + 3 O H_{(a q)}^{-}

, decreasing the conc. of

O H^{-}

ions

\frac{1}{3}

times will cause the equilibrium conc of

F e^{3 +}

to increase __________ times.

Q. In the dissociation of

N H_{4} O H

N H_{4} O H (a q) ⇌ N H_{4}^{+} (a q) + O H^{-} (a q)

N H_{4} C l

is added to it, how will the

p H

for the

N H_{4} O H

solution change?

Q. Assertion :For the analysis of

I I I^{r d}

group basic radicals,

N H_{4} C l

is added to suppress the ionisation of

N H_{4} O H

. Reason: With high concentration of

O H^{-}

ions, basic radicals of other groups also get precipitated with

I I I^{r d}

group basic radicals.

{N H}_{4} C l

is added alongwith

{N H}_{4} O H

in group III to decrease concentration of

{O H}^{-}

ion.

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In III group precipitation NH4Cl is added before adding NH4OH to

The correct option is A decrease conc. of OH−NH4OH⇌NH+4+OH− NH4Cl→NH+4+Cl−Common ion Due to common ion effect, conc. of OH− ion decreases. Thus, precipitation of higher group cations as hydroxides is prevented.

In III group precipitation $N H_{4} C l$ is added before adding $N H_{4} O H$ to

The correct option is A decrease conc. of $O H^{-}$
$N H_{4} O H ⇌ N H_{4}^{+} + O H^{-}$
$N H_{4} C l \to N H_{4}^{+} + C l^{-} Common ion$
Due to common ion effect, conc. of $O H^{-}$ ion decreases. Thus, precipitation of higher group cations as hydroxides is prevented.