Question

In $m_1$ g of a metal A displaces $m_2$ g of another metal B from its salt solution and if their equivalent masses are $E_1$ and $E_2$ respectively, then the equivalent mass of A can be expressed as:

• A. $E_1=\frac{m_2\times E_2}{m_2}$
• B. $E_1=\frac{m_1}{m_2}\times E_2$
• C. $E_1=\frac{m_1\times m_2}{E_2}$
• D. $E_1=\sqrt{\frac{m_1}{m_2}\times E_2}$

Answer 1

The correct option is B $E_1=\frac{m_1}{m_2}\times E_2$

Given-

$m_{1}g$ of metal $A$ displaces $m_{2}g$ of metal $B$ from it's salt solution.

Equivalent mass of $A$ and $B$ are $E_1$ and $E_2$ respectively.

Let's find out the relation b/w $E_1$ and $E_2$.

As we know always equal equivalent of substance reacts.

No. of $gm$ equivalent of $A=$ No. of $gm$ equivalent of $B$

$\therefore \frac{m_1}{E_1}=\frac{m_2}{E_2}$

$\therefore E_1=\frac{m_1}{m_2}\times E_2$
Option B is correct.