In methyl alcohol solution, bromine reacts with ethylene (ethene) to yield $B r C H_{2} C H_{2} O C H_{3}$ in additional to 1, 2-dibromoethane because of $B r^{-} C H_{3} O H$ . Which of the following is correct regarding the reaction?

The methyl alcohol solvates the bromine

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The ion formed initially may react with Br

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This is a free radical reaction

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The reaction follows Markovnikov's rule

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Solution

The correct option is A The methyl alcohol solvates the bromine
The major product is formed because the methyl alcohol solvates bromine.

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B r C H_{2} C H_{2} O C H_{3}

B r C H_{2} C H_{2} O C H_{3}

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