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Question

In N,e,τ and m are representing electron density, charge, relaxation time and mass of an electron respectively, then the resistance of wire of length l and cross-sectional area A is given by

A
2mlNe2Aτ
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B
2mτANe2l
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C
Ne2τA2ml
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D
Ne2A2mτl
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Solution

The correct option is A 2mlNe2Aτ
Since average drift velocity =12eEm×(τ)
Now I=NeA×(Averagedriftvelocity)
I=Ne2AE2ml×τ=Ne2AV2ml×τ
R=VI=2mlNe2τA, where N is electron density.

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