In n-p-n transistor circuit, the collector current is 5mA. If 98% of electrons emitted reach the collector then the emitter current will be

5.1 mA

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8.1 mA

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6.5 mA

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10 mA

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Solution

The correct option is A 5.1 mA
The collector current is $5 m A$
Given that $98$ % of electrons emitted reach the collector
Therefore the emitter current is $I_{e} = \frac{100}{98} \times I_{c} = \frac{500}{98} = 5.1 m A$
Therefore the correct option is $A$

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In n-p-n transistor circuit, the collector current is 5mA. If 98% of electrons emitted reach the collector then the emitter current will be

The correct option is A 5.1 mAThe collector current is 5mAGiven that 98% of electrons emitted reach the collectorTherefore the emitter current is Ie=10098×Ic=50098=5.1mATherefore the correct option is A

The correct option is A 5.1 mA
The collector current is $5 m A$
Given that $98$ % of electrons emitted reach the collector
Therefore the emitter current is $I_{e} = \frac{100}{98} \times I_{c} = \frac{500}{98} = 5.1 m A$
Therefore the correct option is $A$