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In NaCl cry...

Question

In $N a C l$ crystal, $C l^{-}$ ions are in $F C C$ arrangement. Calculate the number of $C l^{-}$ ions in its units.

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Solution

No of sodium ions $= 12 (a t e d g e c e n t r e s) \times 1 / 4 + 1 (a t b o d y c e n t r e) \times 1 = 4$
No of $C h l o r i d e$ $i o n s$ $= 8 (a t c o r n e r) \times 1 / 8 + 6 (a t f a c e c e n t r e s) \times 1 / 2 = 4$

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C l^{-}

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N a - 23 u, C l = 35.5 u

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