CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Valency and Oxidation State

In NiCO4, t...

Question

In $N i (C O)_{4}$ , the oxidation state of Ni is?

A

4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

Zero

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C

2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

8

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D Zero
In nickel tetracarbonyl, the oxidation state for nickel is assigned as zero. The formula conforms to the 18-electron rule. The molecule is tetrahedral, with four carbonyl (carbon monoxide) ligands attached to nickel.

Hence, the correct option is $B$

Suggest Corrections

thumbs-up

3

Similar questions

In $N i {(C O)}_{4}$ the oxidation state of Ni is:

Q. The oxidation number of Ni in

N i (C O)_{4}

+ 2

.

In Ni(CO)₄ the oxidation number of Ni is

a.2

b.0

c.4

d.8

Q. Assertion :Oxidation number of Ni in

N i (C O)_{4}

is taken zero. Reason: The oxidation number of CO has ben taken to be zero.

Q. Arrange the following in increasing order of oxidation state of

N i

.

K_{2} [N i (C N)_{4}], K_{2} [N i F_{6}], N i (C O)_{4}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Oxidation Number and State

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Valency and Oxidation State

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon