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Valency and Oxidation State

In NiCO4, t...

Question

In $N i (C O)_{4}$ , the oxidation state of Ni is?

A

4

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B

Zero

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C

2

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D

8

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Solution

The correct option is D Zero
In nickel tetracarbonyl, the oxidation state for nickel is assigned as zero. The formula conforms to the 18-electron rule. The molecule is tetrahedral, with four carbonyl (carbon monoxide) ligands attached to nickel.

Hence, the correct option is $B$

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Similar questions

In $N i {(C O)}_{4}$ the oxidation state of Ni is:

Q. The oxidation number of Ni in

N i (C O)_{4}

+ 2

.

In Ni(CO)₄ the oxidation number of Ni is

a.2

b.0

c.4

d.8

Q. Assertion :Oxidation number of Ni in

N i (C O)_{4}

is taken zero. Reason: The oxidation number of CO has ben taken to be zero.

Q. Arrange the following in increasing order of oxidation state of

N i

.

K_{2} [N i (C N)_{4}], K_{2} [N i F_{6}], N i (C O)_{4}

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