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In nitropruss...

Question

In nitroprusside ion the iron and NO exists as Fe (II) and NO(I) rather than Fe (III) and NO. These forms can be differentiated by :

A

Estimating the concentration of iron

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B

Measuring the concentration of CN

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C

Measuring the solid state magnetic moment

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D

Thermally decomposing the compound

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Solution

The correct option is C Measuring the solid state magnetic moment
In nitroprusside ion the iron and $N O$ exists as $F e (I I)$ and $N O (I)$ rather than $F e (I I I)$ and $N O .$ These forms can be differentiated by measuring the solid state magnetic moment.

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Similar questions

Q. In nitroprusside ion the iron and

N O

F e^{I I}

N O^{+}

F e^{I I I}

N O

. These forms can be differentiated by :

Q. In nitroprusside ion, the iron and NO exist as

F e^{+ 2}

N O^{+}

F e^{+ 3}

N O

. The given conclusion can be drawn by:

Q. Nitroprusside ion is
A:

[F e^{I I} (C N)_{5} N O^{+}]^{2 +}

[F e^{I I I} (C O)_{5} N O]^{2 +}

. A and B can be differentiated by:

Q. Sulphide ions react with

N a_{2} [F e (N O) {(C N)}_{5}]

to form a purple colored compound

N a_{4} [F e {(C N)}_{5} (N O S)]

In the reaction, the oxidation state of iron :

Q. Chooe the correct amswer using given codes. Use T if statement is true and F if it is false.
(I) Sulphide ions reacts with

N a_{2} [F e (C N)_{5} (N O)]

to form a purple coloured compound

N a_{4} [F e (C N)_{5} (N O S)]

. In the reaction, the oxidation state of iron changes.
(II)

P t (I V)

compounds are relatively more stable than

N i (I V)

compounds.
(III) The welding of magnesium can be done in the atmosphere of helium.
(IV)

L i A I H_{4}

on hydrolysis will give

H_{2}

.

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