Question

In nuclear fission, $0.1\%$ mass is converted into energy. The energy released in the fission of $1$Kg mass in KWH is

• A. $2.5\times 10$${}^5$
• B. $2.5\times 10$${}^7$
• C. $2.5\times 10$${}^9$
• D. $2.5\times 10$${}^{-7}$

Answer 1

The correct option is B $2.5\times 10$${}^7$

$0.$1% Mass is converted.
$E=(\frac{1}{1000}\times 1kg)(3\times {10}^8{)}^{2}J$

$=9\times {10}^{13}J$

Let this energy is librated per second then,
$E$ per hour $=\frac{9\times {10}^{13}}{60\times 60}$$=0.25\times {10}^{11}WH$$=2.5\times {10}^{7}KWH$