In order to fix an electric pole along a roadside, a pit with dimensions $50$ cm $\times$ $50$ cm is dug with the help of a spade. The pit is prepared by removing earth by $250$ strokes of spade. If one stroke of spade removes $500$ cu. cm of earth, then what is the depth of the pit?

2

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Solution

The correct option is D $0.5$ m
Earth removed $= 250 \times 500$ cu. cm
$= \frac{250 \times 500}{(100)^{3}} = \frac{1}{8}$ cu. m
Volume of the pit dug $= \frac{1}{8}$
$\Rightarrow \frac{50}{100} \times \frac{50}{100} \times h = \frac{1}{8}$ $\Rightarrow h = \frac{1}{2}$ m

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In order to fix an electric pole along a roadside, a pit with dimensions 50 cm × 50 cm is dug with the help of a spade. The pit is prepared by removing earth by 250 strokes of spade. If one stroke of spade removes 500 cu. cm of earth, then what is the depth of the pit?

The correct option is D 0.5 mEarth removed =250×500 cu. cm=250×500(100)3=18 cu. mVolume of the pit dug =18⇒50100×50100×h=18 ⇒h=12 m

In order to fix an electric pole along a roadside, a pit with dimensions $50$ cm $\times$ $50$ cm is dug with the help of a spade. The pit is prepared by removing earth by $250$ strokes of spade. If one stroke of spade removes $500$ cu. cm of earth, then what is the depth of the pit?

The correct option is D $0.5$ m
Earth removed $= 250 \times 500$ cu. cm
$= \frac{250 \times 500}{(100)^{3}} = \frac{1}{8}$ cu. m
Volume of the pit dug $= \frac{1}{8}$
$\Rightarrow \frac{50}{100} \times \frac{50}{100} \times h = \frac{1}{8}$ $\Rightarrow h = \frac{1}{2}$ m