The number of planks of dimensions $(4$ m $\times 50$ cm $\times 20$ cm $)$ that can be stored in a pit which is $16$ m long, $12$ m wide and $4$ m deep is

1900

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1920

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1800

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1840

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Solution

The correct option is B $1920$
Given, number of planks of dimensions $(4$ m $\times 50$ cm $\times 20$ cm $)$
Volume of planks $= l b h = 400 (50) 20 = 400000$ cm $^{3}$
Volume of pits $= 1600 (1200) 400 = 768000000$ cm $^{3}$
Number of planks $= \frac{786000000}{400000} = 1920$

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Question 8
The number of planks of dimensions $(4 m \times 50 c m \times 20 c m)$ that can be stored in a pit which is 16 m long, 12 m wide and 4 m deep is:

A) 1900
B) 1920
C) 1800
D) 1840

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Question 8
The number of planks of dimensions $(4 m \times 50 c m \times 20 c m)$ that can be stored in a pit which is 16 m long, 12 m wide and 4 m deep is:

A) 1900
B) 1920
C) 1800
D) 1840

Q. How many planks of dimensions

5 m \times 25 c m \times 10 c m

can be stored in a pit which is

20 m

long,

6 m

wide and

80 c m

deep?

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The number of planks of dimensions (4 m ×50 cm ×20 cm) that can be stored in a pit which is 16 m long, 12 m wide and 4 m deep is

The correct option is B 1920Given, number of planks of dimensions (4m ×50 cm ×20 cm )Volume of planks =lbh=400(50)20=400000 cm3Volume of pits =1600(1200)400=768000000 cm3Number of planks =786000000400000=1920

The number of planks of dimensions $(4$ m $\times 50$ cm $\times 20$ cm $)$ that can be stored in a pit which is $16$ m long, $12$ m wide and $4$ m deep is

The correct option is B $1920$
Given, number of planks of dimensions $(4$ m $\times 50$ cm $\times 20$ cm $)$
Volume of planks $= l b h = 400 (50) 20 = 400000$ cm $^{3}$
Volume of pits $= 1600 (1200) 400 = 768000000$ cm $^{3}$
Number of planks $= \frac{786000000}{400000} = 1920$