In order to obtain a magnification of, -1.5 with a concave mirror of focal length 16 cm, the object will have to be placed at a distance : (a) between 6 cm and 16 cm ,(b) between 32 cm and 16 cm (c) between 48 cm and 32 cm (d) beyond 64 cm

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Solution

Answer: (b) between 32 cm and 16 cm

Explanation: Magnification of -1.5 means that the image is real, inverted and enlarged. This is possible when the object placed between centre of curvature and focus. Here, focus is at 16 cm and centre of curvature is at 2 $\times$ 16 = 32 cm.

Diagram:

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In order to obtain a magnification of, -1.5 with a concave mirror of focal length 16 cm, the object will have to be placed at a distance : (a) between 6 cm and 16 cm ,(b) between 32 cm and 16 cm (c) between 48 cm and 32 cm (d) beyond 64 cm

Answer: (b) between 32 cm and 16 cm Explanation: Magnification of -1.5 means that the image is real, inverted and enlarged. This is possible when the object placed between centre of curvature and focus. Here, focus is at 16 cm and centre of curvature is at 2 × 16 = 32 cm. Diagram: .

Answer: (b) between 32 cm and 16 cm

Explanation: Magnification of -1.5 means that the image is real, inverted and enlarged. This is possible when the object placed between centre of curvature and focus. Here, focus is at 16 cm and centre of curvature is at 2 $\times$ 16 = 32 cm.

Diagram:

.