Question

In order to prepare borazine, we need by diborane and Ammonia in the ratio_____

• A. 5:9
• B. 1:2
• C. 22:23
• D. 3:4

Answer 1

The correct option is B 1:2

Borazine is prepared from diborane. When 3 moles of diborane combines with 6 moles of ammonia on heating, it gives two moles of inorganic benzene and 12 moles of hydrogen molecules, that means we need diborane and Ammonia in the ratio 1:2.
$B_2{H}_6+N{H}_3\underset{ratio2N{H}_3:1B_2{H}_6}{\overset{\text{high temperature}\left({200}^{o}C\right)}{\to }}{B}_3{N}_3{H}_6\text{Borazine}$