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Valency and Oxidation States

In order to p...

Question

In order to prepare one litre $1 N$ solution of $K M n O_{4}$ , how many grams of $K M n O_{4}$ are required, if the solution to be used in acid medium for oxidation?

128 g

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41.75 g

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31.60 g

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62.34 g

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Solution

The correct option is A $31.60 g$
One liter $1 N$ solution of $K M n O_{4}$ corresponds to 1 g equivalent. In acid medium for oxidation, the equivalent weight of $K M n O_{4}$ is one fifth of its molecular mass. It is $\frac{158}{5} = 31.6$ .
Hence, 1 g equivalent of $K M n O_{4}$ corresponds to 31.6 g.
Hence, in order to prepare one liter $1 N$ solution of $K M n O_{4}$ , $31.6$ grams of $K M n O_{4}$ are required, if the solution to be used in acid medium for oxidation.

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In order to prepare one litre 1N solution of KMnO4, how many grams of KMnO4 are required, if the solution to be used in acid medium for oxidation?

In order to prepare one litre $1 N$ solution of $K M n O_{4}$ , how many grams of $K M n O_{4}$ are required, if the solution to be used in acid medium for oxidation?