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Altitude of a Triangle and Drawing Method

In parallelog...

Question

In parallelogram ABCD, AB = 16 cm. The altitudes corresponding to sides AB and AD are respectively 8 cm and 10 cm. Then AD is equal to

12.8 cm

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12.5 cm

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15 cm

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18 cm

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Solution

The correct option is A
12.8 cm

Since the triangles ∆BCQ and ∆BCP are on the same base and their areas are equal, therefore they lie between two parallels.

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In parallelogram ABCD, AB = 16 cm. The altitudes corresponding to sides AB and AD are respectively 8 cm and 10 cm. Then AD is equal to

The correct option is A 12.8 cm Since the triangles ∆BCQ and ∆BCP are on the same base and their areas are equal, therefore they lie between two parallels.

The correct option is A
12.8 cm

Since the triangles ∆BCQ and ∆BCP are on the same base and their areas are equal, therefore they lie between two parallels.