wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

In parallelogram ABCD, rhombus PQRS is constructed by joining midpoints of the sides. Find area of the rhombus if AB and BC are 8 cm and 6 cm respectively.

A
48 cm2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
24 cm2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
36 cm2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
12 cm2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 24 cm2
Given : ABCD is a parallelogram,
AB= 8 cm, BC= 6 cm.
PQRS is a rhombus.

As the rhombus is made from joining the midpoints AD=PR=BC and also they are parallel to each other, similarly AB=SQ=DC and they are also parallel to each other.

we know area of rhombus
= 12×(product of diagonals)
= 12×(PR×SQ)
= 12×(6×8) .....(PR=BC, AB=SQ)
= 482 = 24 cm2

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Area of Parallelogram
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon