Question

In photosynthesis, 6 molecules of carbon dioxide combine with an equal number of water molecules through a complex series of reactions to give a molecule of glucose having a molecular formula $C_6{H}_{12}{O}_6$. How many grams of water would be required to produce 18 g of glucose? Compute the volume of water so consumed assuming the density of water to be $1gc{m}^{-3}$.

Answer 1

$6C{O}_2+6H_{2}O\underset{Sunlight}{\overset{Chlorophyll}{\to }}{C}_6{H}_{12}{O}_6+6O_2$

1 mole of glucose requires 6 moles of water.

180 g of glucose requires (618) g of water.

1 g of glucose will require$\frac{108}{180}g$ of water.

18 g of glucose would need $\frac{108}{180}$ 18g of water $=10.8g$

$Volumeofwaterused$ $=$ $\frac{Mass}{Density}$ $=\frac{10.8g}{1gc{m}^{-3}}$ $=10.8c{m}^3$