Question

In photosynthesis, 6 molecules of carbon dioxide combine with an equal number of water molecules through a complex series of reactions to give a molecule of glucose having a molecular formula $C_6{H}_{12}{O}_6$. How many grams of water would be required to produce 18 g of glucose?

Answer 1

$6C{O}_2+6H_{2}O=\frac{Chlorophyll}{Sunlight}{C}_6{H}_{12}{O}_6+6O_2$
$1$ mole of glucose needs $6$ moles of water.
$180$ g of glucose needs $(6\times 18)$ g of water.
$1$ g of glucose will need $\frac{108}{180}$ g of water.
$18$ g of glucose would need $\frac{108}{180}\times 18$ g of water $=10.8$g.
Volume of water used $=\frac{Mass}{Density}=\frac{10.8g}{1gc{m}^{-3}}=10.8c{m}^3$.