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If Two Sides of a Triangle Are Unequal, Then the Angle Opposite to the Greater Side Is Greater Than Angle Opposite to the Smaller Side

In PQR , PR >...

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In ∆PQR, PR > PQ, PA is the bisector of angle P and PM is perpendicular to QR. Prove that angle APM = 1/2 ( angle Q - angle R).

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In triangle PQR, Q > angle R; PA is the bisector of angle QPR ; PM IS perpendicular to PR .prove that angle APM=1/2(angle Q - angle R).

Q. In the figure,

∠ Q > ∠ R

, PA is the bisector of

∠ Q P R

P M ⊥ Q R

∠ A P M = 1 / 2 (∠ Q - ∠ R)

6.57

∠ Q > ∠ R

P A

is the bisector of

∠ Q P R

P M ⊥ Q R

∠ A P M = \frac{1}{2} (∠ Q - ∠ R)

.

Q. Question 7
In the given figure,

∠ Q > ∠ R

, PA is the bisector of

∠ Q P R

⊥

∠ A P M = \frac{1}{2} (∠ Q - ∠ R)

Q. Question 7
In the given figure,

∠ Q > ∠ R

, PA is the bisector of

∠ Q P R

⊥

∠ A P M = \frac{1}{2} (∠ Q - ∠ R)

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If Two Sides of a Triangle Are Unequal, Then the Angle Opposite to the Greater Side Is Greater Than Angle Opposite to the Smaller Side

Standard IX Mathematics

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