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Question

In ∆PQR, right angled at Q and ∠P = ∠R, then sin P cos R + cos P sin R is


A

1

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B

1/√2

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C

√3/2

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D

1/2

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Solution

The correct option is A

1


By angle sum property ∠P = ∠R = 45o

cos45o = 1/√2 , sin 45o = 1/√2, substituting these values, we get

sin P cos R + cos P sin R = 1


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