In - PQR- right angled at Q and - P - R- then sin P cos R -cos P sin R isA- 1B- 1 - -2C- 1 - 2D- -3 - 2

The correct option is A 1By angle sum property ∠P = ∠R = 45o cos45o = 1/√2 , sin 45o = 1/√2, substituting these values, we get sin P cos R + cos P sin R = 1 ...

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Standard X

Mathematics

Standard Values of Trigonometric Ratios

In Δ PQR, rig...

Question

In ∆PQR, right angled at Q and ∠P = ∠R, then sin P cos R + cos P sin R is

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¹/_√2

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^√3/₂

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¹/₂

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Solution

The correct option is A
1

By angle sum property ∠P = ∠R = 45^o

cos45^o = ¹/_√2 , sin 45^o = ¹/_√2, substituting these values, we get

sin P cos R + cos P sin R = 1

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