CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question

In problem 10.9, if 15.0 cm of water and spirit each are further poured into the respective arms of the tube, what is the difference in the levels of mercury in the two arms? (Specific gravity of mercury = 13.6)

Open in App
Solution

Height of the water column, h1=10+15=25cm
Height of the spirit column, h2=12.5+15=27.5cm
Density of water, ρ1=1gcm3
Density of spirit, ρ2=0.8gcm3
Density of mercury = 13.6gcm3
Let h be the difference between the levels of mercury in the two arms.
Pressure exerted by height h, of the mercury column:
=hρg=h×13.6g.........(i)
Difference between the pressures exerted by water and spirit:
=h1ρ1gh2ρ2g
=g(25×127.5×0.8)=3g.....(ii)
Equating equations (i) and (ii), we get:
13.6 hg = 3g
h=0.2205880.221cm
Hence, the difference between the levels of mercury in the two arms is 0.221 cm.


flag
Suggest Corrections
thumbs-up
5
BNAT
mid-banner-image