In radioactive decay 90Th234→92Th234 the number of α and β - particles emitted respectively are
A
1,2
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B
2,0
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C
0,2
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D
2,1
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Solution
The correct option is C0,2 There is no change in mass number, hence no α particles are emitted. Atomic number increased by 2 ⇒ 2 β particles are emitted.