In reaction C6H5CH3 ⟶Oxidation A ⟶NaOH BSodalime−−−−−→ C Then 'C' is
a) C6H5CH3 [O]−→ C6H5COOH[A] NaOH−−−−→ C6H5COONa[B] NaOH/CaO−−−−−−−→C6H6[C]
Given f(x) = ax2+bx+c
If f(m) = a - b + c
f(n) = 4a + 2b + c
f(p) = a + b + c
Then, m + n + p = __
An element X reacts with dilute H2SO4 as well as with NaOH to produce salt and H2(g). Hence, it may be concluded that:
A. X is an electropositive element. B. Oxide of X is basic in nature C. Oxide of X is acidic in nature. D. X is an electronegative element.