In Reaction- Cr2O72-14H-6e- gives 2Cr3- - 7H2O- what is the quantity of electricty in coulombs needed to reduce 1mol of Cr2O72-

According to the given equation, to reduce 1 mole of Cr2O7 nbsp;2 , the required quantity of electricity will be: =6 F = 6 times; 96487 C = 578922 C ...

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Standard XII

Physics

Work Function

in Reaction, ...

Question

in Reaction, Cr₂O₇²^-+14H⁺+6e^- gives 2Cr³⁺ + 7H₂O, what is the quantity of electricty in coulombs needed to reduce 1mol of Cr₂O₇^2-?

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Solution

According to the given equation, to reduce 1 mole of Cr₂O₇ ^2-, the required quantity of electricity will be:

=6 F

= 6 × 96487 C

= 578922 C

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Q. Consider the reaction :

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C r_{2} O_{7}^{2 -} (a q) + 14 H^{\oplus} (a q) + 6 e^{-} \to 2 C r^{3 +} (a q) + 7 H_{2} O

can be represented as:

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C r_{2} O_{7}^{2 -} (a q) + 14 H^{+} (a q) + 6 e \to 2 C r^{3 +} (a q) + 7 H_{2} O

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in Reaction, Cr2O72-+14H++6e- gives 2Cr3+ + 7H2O, what is the quantity of electricty in coulombs needed to reduce 1mol of Cr2O72-?

According to the given equation, to reduce 1 mole of Cr2O7 2-, the required quantity of electricity will be: =6 F = 6 × 96487 C = 578922 C

in Reaction, Cr₂O₇²^-+14H⁺+6e^- gives 2Cr³⁺ + 7H₂O, what is the quantity of electricty in coulombs needed to reduce 1mol of Cr₂O₇^2-?

According to the given equation, to reduce 1 mole of Cr₂O₇ ^2-, the required quantity of electricity will be:

=6 F

= 6 × 96487 C

= 578922 C